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What mass of lead (in grams) is deposited at the cathode over those 15.6 mins in a galvanic cell

Submitted by VCU12 on Wed, 04/30/2008 - 10:21

A galvanic cell generates an average current of .121 amps for 15.6 min.  The half reaction at the cathode is : Pb+2(aq) + 2e- ---> Pb (s)
What mass of lead (in grams) is deposited at the cathode over those 15.6 mins

My teacher didn't really go over this that well, and our final is on friday, if someone could help me that would be great! Thank you very much!


Faraday, unit of electrical charge equal to the charge on one mole of electrons. Its value is 9.648 x 104 coulombs/mol.
1 amp= 1 coulumb/sec
Charge = .121 coulumbs /sec  x 60 sec/1 min  x 15.6 min

moles of electrons =  charge (calculated above)/ 96480 Coulombs/mol

moles of Pb = 1/2 moles of electrons

Convert moles of Pb to grams.