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-the solubility of AgCl in water at 25c is 1.274*10^2, on the assumption that the Debye–Hückel limiting law apply

-the solubility of AgCl in water at 25c is 1.274*10^2, on the assumption that the Debye–Hückel limiting law apply. 


a-calculate ∆G for the process of AgCl gives Ag+ + Cl- 
b- the solubility for the AgCl in 0.005 K2SO4 solution.

 

I really appreciate the help.

valdorod Fri, 04/25/2014 - 01:46

for the solubility of an ionic compound where the cation to anion ratio is 1 to 1 the formula is

 

Ksp = x2   where x is the molar solbility

∆G = -RT ln(Ksp)

 

for b you have to see if any of the ions in K2SO4 interact with either Ag+ or Cl-  if they do not then nothing changes if they do, you have to take that equilibrium into account.  In other words will either KCl or Ag2SO4 be formed?