Skip to main content

Percentage of Acetic Acid in Vinegar Lab

Submitted by 571037 on Sat, 01/05/2013 - 17:00

 How do you calculate the molarity of NaOH, given these mesurements?

 

Measurements and Results

#1

#2

Mass of flask and vinegar

135.79g

114.09g

Mass of empty flask

125.97g

104.24g

Mass of vinegar

9.82g

9.85g

Final reading of buret

10.5mL

20mL

Initial reading of buret

0mL

10.5mL

Volume of NaOH used

10.5mL

9.5mL

Moles of NaOH used

 

 

Moles of acetic acid in vinegar

 

 

Mass of acetic acid in vinegar

145.74g

123.73g

Percentage of acetic acid in vinegar

 

 

                                                                                                                                                                                                                                                                                                      

 


As I have already explained, you find the number of moles acetic acid from its mass/molar mass. Then from the balanced reaction  equation you can find the number of moles of NaOH that are needed to react with the calculated moles of acetic acid. Then molarity of NaOH = number of moles NaOH/volume used in the titration in LITRES