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Measuring how much heat must be added to the water to raise its temperature to 29oC

Submitted by Anonymous (not verified) on Mon, 08/04/2008 - 20:19

Same concept as the last post, I know, but this time there's density involved.  :o

"A swimming pool, 20.0 m X 12.5 m, is filled with water to a depth of 3.75 m. If the initial temperature of the water is 18.4oC, how much heat must be added to the water to raise its temperature to 29oC? Assume that the density of water is 1.000 g/mL."

I need mass, but they give density. Is there a way to convert it or something so I have mass?


You need to first calculate the volume of the swimming pool in cubic meters:
               Volume = length x width  x depth

Next multiply the volume in cubic meter by the conversion factor
                          ( 102 cm / 1 m )3  or  106 cm3 / 1 m3

Now that you have volume in cm3, you can determine the mass by multiplying the volume times the density.

Once you have the mass, you can plug into your heat formula and find the amount of heat that must be absorbed by the water.