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# How much mass would 2 atoms of silver have

Submitted by Cperez on Sun, 09/23/2012 - 22:35
How much mass would 2 atoms of silver have

Divide the molar mass of Ag (107.86 grams) by the number of atoms in a mole (6.02 x 1023 atoms)

At mass of Ag=107.86 amu I mole of Ag= 107.86 g = 6.02×20^23 atoms of Ag Mass of one atom of Ag= 107.86/6.03×10^23g Mass of two atoms of Ag= 2×107.86/6.02×10^23g =3.58×10^24 g

At mass of Ag=107.86 amu I mole of Ag= 107.86 g = 6.02×10^23 atoms of Ag Mass of one atom of Ag= 107.86/6.02×10^23g Mass of two atoms of Ag= 2×107.86/6.02×10^23g =3.58×10^24 g

Molar mass of Ag=107.86g No of atoms in one mole of Ag=6.02×10^23 Mass of one atom of Ag= 107.86/6.02×10^23g =1.79×20^24g Mass of two atoms of Ag=2×1.79×19^24g =3.58×10^24g

Mass of two atoms of Ag = 2×107.86/6.02×10^23= 3.58×10^-24g or Mass of two atoms of Ag=2×107.86×1.66×10^-24=3.58×10^-24g ( 1u =1.66×10^-24g)

Mass of two atoms of Ag= 2×107.86/6.022×10^23g=3.58×10^-22g

1mol of silver has mass 107.87g
This is the mass of 6.022*10^23 atoms
mass of 1 atom = 107.87/6.022*10^23 = 1.79*10^-22g
2 atoms will have mass = 3.58*10^-22g

Regards,

Rita Martin

www.worldofchemicals.com