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How many kilograms of limestone should be added for every kilogram of iron ore processed in a blast furnace?

Submitted by outlandish on Fri, 10/12/2012 - 09:35

 

How many kilograms of limestone should be added for every kilogram of iron ore processed in a blast furnace if the limestone is 93.80% pure and the iron ore contains 12.00% SiO2 by mass? (Note: SiO2(s) + CaCO3(s) → CaSiO3(s) + CO2(g))

 

SiO2(s) + CaCO3(s) → CaSiO3(s) + CO2(g))
This balanced equation indicates that 1 mole of SiO2 reacts with 1 mole of CaCO3 to produce 1 mole of CaSIO3 and 1 mole of CO2.

molar mass of SiO2 = 60.1 g
molar mass of CaCO3 =100.1 g
so it means that 60.1 grams of SiO2 will completely react with 100.1 grams of CaCO3. 
 

The iron ore contains 12.00% SiO2 by mass which means that 100 g of iron ore contais .12 g of SiO2. and the limestone is 93.80% pure  which means it contains .938 g of CaCO3

determine the mass of iron ore that contain 60.1 grams of SiO2, and the mass of limestone contained in 100.1 grams of CaCO3.

grams of SiO2 / grams of iron ore = 0.12
Mass of iron ore in grams =  60.1/0.12 = 500.83 g

similarly,mass of limestone IN GRAMS =106.7 g

ITHIS tells you that 106.7 grams of limestone reacts with 500.83 grams of iron ore.

now,to find how many kilograms of limestone should be added for every kilogram of iron ore
Convert masses to kilograms. using equivalent ; 1 kilogram = 1000 g
0.1067 kg of limestone reacts with 0.50083 kg of iron ore,now find kgs of limestone for 1 kg of Fe by yourself.