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Help with caluculating volume....

Submitted by OrganicMama on Fri, 09/11/2009 - 11:30

I need help with two questions:

First part:

What is the volume, in cubic inches, of a gold nugget that has a mass of 82.00 ounces?
Density of Au = 19.3 g/cm3 ; 453.6 g = 1lb ; 16 ounces = 1lb 16.4 cm3 = in3

THEN second part:

Jim has a block of aluminum that has the same volume as the gold in question 4. What is the mass in grams of this aluminum block? Den of Al = 2.70 g/cm3

Now here are my calculations to part one, which dont look right... but I tried!! I really need to learn this... UGH

M = 82.00 ounces = 82.00-oz / 16-oz/lb = 5.125-lbs
D = 19.3-g/cm^3 = 19.3-g/cm^3 / 453.6-g/lb = 0.04-lb/cm^3
V = 5.125-lbs / 0.04-lbs/cm^3 = 128.125-lb/cm^3
V = 128.125-lb/cm^3 x 16.4-cm^3/in^3 = 2101.25-lb/in^3

so THIS , No??


I noticed I thinkthe LAST calulation I did is wrong I think....

so here are my ANSWERS AGAIN: 

4. What is the volume in cubic inches of a gold nugget that has a mass of 82.00 ounces?

M = 82.00 ounces = 82.00-oz / 16-oz/lb = 5.125-lbs
D = 19.3-g/cm^3 = 19.3-g/cm^3 / 453.6-g/lb =  0.04-lb/cm^3
V = 5.125-lbs / 0.04-lbs/cm^3 = 128.125-lb/cm^3
V = 128.125-lb/cm^3 / 16.4-cm^3/in^3 = 7.81-lb/in^3

Answer:  7.81-lb/in^3

5. If den of Al is 2.70-g/cm^3 with the same volume as the gold in question 4 then:

D=M/V

7.81-lb/in^3  x  16.4-cm^3 = 128.125-lb/cm^3 =  V    then

128.125-lb/cm^3 x 453.6-g/cm^3 = 58117.5-g/cm^3 = V

2.70-g/cm^3  =  M  /  58117.5-g/cm^3  = 156917.25-g/cm^3

Answer:  156917.25-g/cm^3