Skip to main content

give the orbital destinations of electrons with the following quantum numbers

give the orbital destinations of electrons with the following quantum numbers - (you will get answer like 2p, 3d, etc. ) A. n=3 , l=0, m=0 B. n=2 , l=1, m=-1 C. m=4, l=3, m1=-2 D. m=4, l=2 , m1= 0 thank you

kingchemist Mon, 10/10/2011 - 04:09

n = principle quantum number (energy level) with values of 1, 2, 3, 4 etc

l = angular momentum quantum number with values of 0,1,2,3 to n-1 (l is always at least '1' less than n - this defines the orbital. All s orbitals have l=0, all p orbitals have l=1, all d oribitals have l=2 etc. If n=3 an electron with l=1, m=-1 and s=+1/2 will be in a 3p orbital with the orientation -1 and have a spin of +1/2

m = magnetic quantum number - this defines the orientation in space of the orbital and 2l+1 gives the number of orbitals. So if l=0, 2l+1 = 1 (an s orbital with the value 0); if l=1, then 2l+1 = 3 (p orbitals which have the value -1,0 and +1; if l=2, there are 5 orbitals (d orbitals) with the values -2,-1,0,+1,+2 etc

s = spin quantum number with values of +1/2 or -1/2. Electron in the same orbital will have the same values for n, l and m but will have a different spin quantum number. eg an electron in the 3s orbital has n=3, l=0, m=0 but may have a spin of +1/2 or -1/2