Skip to main content

Enthalpy change with 0.5 mol of propane?

Submitted by caseybartlemay on Wed, 07/17/2013 - 20:22

I'm having issues with this one:

 

Given the balanced chemical equation for the combustion of propane below, what would be the enthalpy change for the combustion of 0.5 mol of propane?

C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) ΔHrxn = -2044 kJ

C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) ΔHrxn = -2044 kJ

this balanced equation tells you that  1 mole of propane C3H8 has ΔHrxn = -2044 kJ , so 0.5 mol ?

equivalence , is 1 mole of C3H8  = -2044 kJ\

0.5 mol C3H8  x -2044 kJ / 1 mol C3H8 = ? kJ