A 140 sample of mercury and a 390 sample of iron are at an initial temperature of 25.0. 250 of heat is applied to each sample.

SUBSTANCE

SPECIFIC HEAT

Iron

0.106

Mercury

0.033

What is the final temperature of mercury sample?

Amount of heat q = cmDeltaT where c=specific heat capacity, m= mass and deltaT= temperature change. You have all but DeltaT so solve. Once you know DeltaT and the starting temperature, you can easily find the final temp (= DeltaT + starting temperature

Amount of heat q = cmDeltaT where c=specific heat capacity, m= mass and deltaT= temperature change. You have all but DeltaT so solve. Once you know DeltaT and the starting temperature, you can easily find the final temp (= DeltaT + starting temperature