Given the following concentration, convert it into the other three units of concentration.

a. 1.5 %(w/w) KMnO4 in 18-Crown-6 ether (C12H24O6, ρSol = 1.237 g/mL)

Thanks

1.5% means 1.5g KMnO4 per 100g ether or 80.84mL of ether (if the value given is the density of ether.)

If it is the density of the solution, then 1.5% means 1.5g KMnO4 per 100g solution or 80.84mL of solution. So mass of ether would be 98.5g. Molarity would be (1.5/molar mass of KMnO4)/0.08084

Molality would be moles of KMnO4/mass of solvent in kg

1.5% means 1.5g KMnO4 per 100g ether or 80.84mL of ether (if the value given is the density of ether.)

If it is the density of the solution, then 1.5% means 1.5g KMnO4 per 100g solution or 80.84mL of solution. So mass of ether would be 98.5g. Molarity would be (1.5/molar mass of KMnO4)/0.08084

Molality would be moles of KMnO4/mass of solvent in kg