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Conversions help

Submitted by Anonymous (not verified) on Mon, 09/07/2009 - 11:52

How many in3 are 568 cm3?

For this problem i know (2.54 cm = 1 in.) m question is do i do this.
so would i do
568cm^3/1 X 1in^3/2.54^3cm^3 =163in^3

and for this i have no clue where to start
How many pounds does 45.9 in3 of gold weigh?
I am pretty sure i need to use this
The density of gold is 19.3 g/cm3, 2.54 cm = 1 in, and 454 g = 1 lb


Also what is wrong with this.

Convert 388 nm to m. (1 nm = 10-9m)
388nm/1 X 10^-9m/1nm = .00000388 then 3.88e-6


(x in3/568cm3) = 1 in3/16.387064cm3
x = 568/16.387064 = 34.6615 in3

388nm = 388 x 10-9m = 3.84 x 10-7m

1 cm3 gold weighs 19.3 g
16.387064cm3 = 1 in3
1 cm3 = (1/16.387064) in3 = 0.0610 in3

584 g Au weighs 1lb
19.3 g Au weighs  (1/584) x 19.3 = 0.0330 lb

0.0610 in3 weigh 0.0330 lb
45.9 in3 weigh (0.0330/0.0610) x 45.9 lb