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# can someone provide me with a step by step answer to this equation?

Submitted by cdailor on Wed, 06/18/2014 - 17:52

A 3.8 x 10^-2 kg sample of silver has a volume of 3.6 x 10^6 nL. Calculate the density of silver in g/mL and g/cm^3.

Never really heard of a nL before, but it must be a nanoliter (1 x 10-9 L)

This really is just a unit conversion problem:

3.8 x 10-2 kg      x     ( 103 g / 1 kg )   =   38 g

3.6 x 106 nL       x      ( 1 L / 109 nL )   =   3.6  x 10-3 L

and  3.6 x 10-3 L    x   (  103 mL / 1 L )   =  3.6 mL

3.6 mL       x  (   1 cm3 / 1 mL  )    =  3.6 cm3

(NOTE:  In each of the above conversions, I multiplied by a conversion factor that had the units I was going to on top, over the unit that I was coming from on the bottom.  When I do a conversion problem I do it in two steps, first determine the units for the conversion factor, and then determine the numbers that go with the units.)

Now plug into the density formula:

density =  mass / volume

Need step to step answers for these equations.