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Calculate [N2O4] at equilibrium when [NO2]=2.00×10−2mol/L.?

Submitted by wnterhorst on Sat, 09/20/2014 - 11:20

Calculate [N2O4] at equilibrium when [NO2]=2.00×10−2mol/L.?

 
For the reaction N2O4(g)⇌2NO2(g), the value of K at 25∘C is 7.19×10−3. 


i would like to see the math behind it so i can understand it better. 

thanks in advance

wnterhorst:

Here is the solution with all steps and algebra demonstrated. Hope this helps.

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