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Calculate the ionization energy for H atom when the electron is in n=1 and in another case where n=2 level

Submitted by saiyanmx89 on Fri, 04/17/2009 - 00:25

The ionization energy of the hydrogen atom is the energy required to remove its electron. Calculate the ionization energy of hydrogen atoms (J/atoms) for the electron:

in first orbital:
E = (-2.2x10^-18)/1^2 = -2.2x10^-18 J

in second orbital:
E = (-2.2x10^-18)/2^2 = -5.5x10^-19 J

Did I do these two right????

Seems right to me.

Z = atomic number, which is 1 for H.
n = valence

So, I would say yes.

I don't believe you need second answer. Hydrogen only has 1 electron. So there is no second orbital.

Hydrogen has a IE of 1312 kJ/mol only.

Which, if you use your first orbital number in J and convert to kJ you get:

-2.178 x 10^-18 J/atom x 6.022 x 10^23 atom/mol = 1.31 x 10^6

-1.31 x 10^6 J/mol x 1 kJ/1000J = roughly -1311.59 kJ/mol.

Not far off from 1312.