Homework help! Got a migraine with this one!
CH3CH2CHO + O2 (yeilds) CH3CHO +H2O
all of the numbers in the above equation are subscript.
Are you sure you have the correct equation? Generally when you have a hydrocarbon(plus an oxygen) in the presence of oxygen, it yields carbon dioxide and water. I have never come across a reaction that has an aldehyde in the presence of oxygen turning into a shorter chained aldehyde and water.
I tried solving the eqn and I had a 2 in front of the first compound and a 3 in front of the third compound, and then I got stuck.
The equation is part of a 5 mole problem from Prentice -Hall Text 'Chemistry and Life, an intro to general, organic, and biological chemistry, Sixth Edition. It is Ch. 4 question #54. The actual question reads:
Acetaldehyde, CH3CHO,(d=0.788g/mL), a liquid used in the manufacture of perfumes, flavors dyes and plastics, can be produced by the reaction of ethanol with oxygen.
CH3CH2OH + O2 (yeilds) CH3CHO +H2O (all #'s are subscript) (not balanced)
How many liters of liquid ethanol (d=0.789 g/mL) must be consumed to produce 25.0L of acetaldehyde?
Any help would be appreciated!
i see why maddy couldn't get it, you had an extra carbon in the first one
using this equation
CH3CH2OH + O2 (yeilds) CH3CHO +H2O
2 and 2
so it is balanced. some one check me here.
save O2 for last
start with C
you have 2 on left and 2 on right so that is good
you have 6 on left and 6 on right so that is good
now for O2
3 on right and 2 on left so we need to use a fraction
the O2 come with 2 O and we can't do anything about that but if we take 1/2 of O2 then that will represent one O
so CH3CH2OH + 1 /2 O2 (yeilds) CH3CHO +H2O
now some teachers won't allow you to leave the fraction so you multiply everything by 2
2 CH3CH2OH + O2 (yeilds) 2 CH3CHO + 2 H2O
Thanks! That really made sense when you put it that way.
hey do me a favor and tell your friends OK!
Having the correct chemical equation would have been very helpful >:|