A solution was prepared such that the initial concentrations of Cu+2 and CN- were 0.0120 M and 0.0400 M, respectively. these ions react according to the following equation - Cu2+ + 4CN- > Cd(CN)4 ^2-. Kc = 1.0 x 10^25. What will be the concentration of CN- at equilibrium?
I made an ICE table and plugged everything into Kc,
so 1.0 x 10^25 = x / (0.0120 - x)((.04-4x)^4), is that right so far?