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What is the minimum volume of 6.00 M HCl necessary to neutralize completely the hydroxide in 750.0 ml of 0.107 M NaOH?

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First write down balanced reaction between NaOH and HCl

 One mole of NaOH reacts with mole of HCl to give Salt and water. At the neutralization point moles of NaOH reacted with  HCl Should be same. We know that molarity is equal to moles/ vol in  L. It means moles are equal to molanty times Volume. So

M1V1(NaOH)= M2V2(HCl)

 So plug in the values and calculate volume of HCl.


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