Re: Close-packed arrangement question
Any help with the following question would be greatly appreciated!
The diameter of a rubidium atom is 4.95 Å. We will consider two different ways of placing the atoms on a surface. In arrangement A, all the atoms are lined up with one another. Arrangement B is called a close-packed arrangement because the atoms sit in the "depressions" formed by the previous row of atoms.
A) Using arrangement A, how many Rb atoms could be placed on a square surface that is 1.0 cm on a side?
B) How many Rb atoms could be placed on a square surface that is 1.0 cm on a side, using arrangement B?
I was able to get A) answer = 4.1 x 1014 atoms/cm2, but I am really confused as to how to find out B) answer should be: 4.7 x 1014 atoms/cm2.
Thank you for your time!
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