In one process 6.00 kg of CaF_{2} are treated with an excess of H_{2}SO_{4} and yield 1.26 kg of HF. Calculate the percent yield of HF.

In one process 6.00 kg of CaF_{2} are treated with an excess of H_{2}SO_{4} and yield 1.26 kg of HF. Calculate the percent yield of HF.

## So, theoretical yield is what

So, theoretical yield is what you need to find and actual yield ins given to yo,for this you need the stoichiometry method and you have to begin with writing the balanced equation:

CaF2 + H2SO4 ------> 2HF + CaSO4

1 mol of CaF2 reacts with excess H2SO4 to form 2 mol of HF.

So, now find out how many moles will form with 6 kg of CaF2, convert kg to grams then grams to moles

6000 g and using the molar mass of CaF2 , 6000/ 78.07 = 76.85 moles

76.85 moles CaF2 x 2 moles HF / 1 mol CaF2 = ? Mol of HF

You found theoretical yield of HF. And actual yield is given, now simply use the formula of percent yield to calculate percent yield of HF