Molarity calculation for a solution using the mass of solute used, the molar mass of solute and the volume of the solution

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hey

does this make sense my calculations?
number of ca2+ moles okay so
o.00969L x 0.0100M x 0.01L = 9.69x10^-6
or
0.00969x 0.0100 =9.69x10^-5 since edta and ca2+ are 1:1 they are the same moles?

can you help me get at least that far?

student wrote:
does this make sense my calculations?
number of ca2+ moles okay so
o.00969L x 0.0100M x 0.01L = 9.69x10^-6
or
0.00969x 0.0100 =9.69x10^-5 since edta and ca2+ are 1:1 they are the same moles?

what the exact question?