If 0.72g of Al is reacted with 17.0mL of 2.4 M KOH, which one is the limiting reagent
A sample of 0.72g of AL is reacted with 17.0mL of 2.4 M KOH. Which one is the limiting reagent?
I came up with the formula as such 2Al(s)+2KOH(aq)+6H2O(l) yields 2KAl(OH)4 (aq)+3H2(g).
I went ahead and decided that I needed to get the moles of Aluminum and KOH by such methods: 17.0mL=0.0170L KOH X (2.4mol KOH/ 1L KOH)=0.0408 mol KOH/2
Then for aluminum: 0.72g Al/26.98g mol Al= 0.0267 mol Al/2
My final ratio was 0.0204mol KOH/0.0134mol Al. Since Al was the smallest number I decided that it was the limiting reagent. Is that correct? And how would one go about finding the theoretical yield of the product, KAl(OH)4 formed if say 1.0g of the Al reacted with the KOH?