# How many Rh atoms would have to be placed side by side to span a distance of 6.0 microm

An atom of rhodium (Rh) has a diameter of about 2.5 x 10^-8cm

- What is the radius of a rhodium atom in angstroms and in meters

- How many Rh atoms would have to be placed side by side to span a distance of 6.0 um(if confused about u in um it looks like a u with a longer line on the left side....dont know wut the symbols called)

- If the atom is assumed to be a sphere what is the volume in m63 of a single Kr atom.

Please explain!!

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An atom of rhodium (Ph) has a diameter of about 2.5 x 10

^{-8}cm- What is the radius of a rhodium atom in angstroms and in meters?

1 cm = 1 centimeter = 1/100 of a meter = 1 x 10

^{-2}m1 angstrom = 1 Å = 1 x 10

^{-10}m(2.5 x 10

^{-8}cm) x (1 x 10^{-2}m/ 1 cm) = 2.5 x 10^{-10}m(2.5 x 10

^{-8}cm) x (1 x 10^{-2}m/ 1 cm) (1 Å/1 x 10^{-10}m) = 2.5 Å- How many Rh atoms would have to be placed side by side to span a distance of 6.0 um(if confused about u in um it looks like a u with a longer line on the left side....dont know wut the symbols called)

1 μm = 1 micrometer = 1 x 10

^{-6}m(μ is a greek letter used to abbreviate the prefix micro, it does look like a u with a tail)

(6.0 μm) x (1 x 10

^{-6}m/1 μm) = 6.0 x 10^{-6}mHow many times does a diameter of 2.5 x 10

^{-10}m fit into 6.0 x 10^{-6}m?6.0 x 10

^{-6}m/2.5 x 10^{-10}m = 2.4 x 10^{-4}timesThe volume of a sphere can be calculated as

V = (4/3) x (pi) x r

^{3}You can use the approximation pi = 3.14, and r = 2.5 x 10

^{-10}m/2 = 1.25 x 10^{-10}m to calculate the volume in m^{3}(cubic meters)V = (4/3) x (3.14) x (1.25 x 10

^{-10}m)^{3}= (4/3) x (3.14) x (1.95 x 10^{-30}m^{3}) = 8.2 x 10^{-30}m^{3}KMST

Mon, 2011-08-15 14:01