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How many Rh atoms would have to be placed side by side to span a distance of 6.0 microm

An atom of rhodium (Rh) has a diameter of about 2.5 x 10^-8cm

- What is the radius of a rhodium atom in angstroms and in meters

- How many Rh atoms would have to be placed side by side to span a distance of 6.0 um(if confused about u in um it looks like a u with a longer line on the left side....dont know wut the symbols called)

- If the atom is assumed to be a sphere what is the volume in m63 of a single Kr atom.

Please explain!!

An atom of rhodium (Ph) has a diameter of about 2.5 x 10-8 cm


- What is the radius of a rhodium atom in angstroms and in meters?


1 cm = 1 centimeter = 1/100 of a meter = 1 x 10-2 m


1 angstrom = 1 Å = 1 x 10-10 m


(2.5 x 10-8 cm) x (1 x 10-2 m/ 1 cm) = 2.5 x 10-10 m


(2.5 x 10-8 cm) x (1 x 10-2 m/ 1 cm) (1 Å/1 x 10-10 m) = 2.5 Å


- How many Rh atoms would have to be placed side by side to span a distance of 6.0 um(if confused about u in um it looks like a u with a longer line on the left side....dont know wut the symbols called)


1 μm = 1 micrometer = 1 x 10-6 m


(μ is a greek letter used to abbreviate the prefix micro, it does look like a u with a tail)


(6.0 μm) x (1 x 10-6 m/1 μm) = 6.0 x 10-6 m


How many times does a diameter of 2.5 x 10-10 m fit into 6.0 x 10-6 m?


6.0 x 10-6 m/2.5 x 10-10 m = 2.4 x 10-4 times


The volume of a sphere can be calculated as


V = (4/3) x (pi) x r3


You can use the approximation pi = 3.14, and r = 2.5 x 10-10 m/2 = 1.25 x 10-10 m to calculate the volume in m3 (cubic meters)


V  = (4/3) x (3.14) x (1.25 x 10-10 m)3 = (4/3) x (3.14) x (1.95 x 10-30 m3) = 8.2 x 10-30 m3




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