How many moles of a substance will be needed to fully react with another substance?

×

Error message

Warning: Illegal string offset 'theme_pager_link' in cleanpager_theme_registry_alter() (line 338 of /home/yeahchemistry/public_html/sites/all/modules/cleanpager/cleanpager.module).
hey

. How many moles of Na2S2O3 are needed to react completely with 42.7 g of AgBr?

Write down the balanced

Write down the balanced equation first

Convert 42.7g AgBr ----> moles of AgBr ----> moles of  Na2S2O3 using molar ratio from balanced reaction.

Na2S2O3 + AgBr → NaBr + Na3

Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2]

First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation:

balancing Na:

2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2]

and everything is now balanced so we've got the balanced equation

molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol

mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr

from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2

so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr]

= 0.455 mol Na2S2O3 (to 3 sig figs)

Karen Heinz