calculation of ca2+ moles in the 10mL hard water sample and ppm
not sure how to but here is my attempt
(0.00969L)(0.01000M)(.0010L) does that look right
or do i leave the 10mL out?
my average EDTA titration:13.65mL
calculate total moles of Mg2+ + Ca2+ in the 10mL hard water sample
since its the EDTA to Ca2+ is a 1:1
do i take the moles from the calcium and multiple it by the volume of EDTA x 10mL?
CALCULATION OF Mg2+ moles in the 10mL hard water sample
EDTA-Ca2+=Mg2+ so if i find the top two subtract it from each other and get magnessium?