The specific heat of water is 4.18 J/g^{o}C. Calculate the molar heat capacity of water.

How do I set this equation up?

chrisf

Fri, 2009-03-06 09:12

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I'm pretty sure....

4.18J/gC * (18.02g/mol) = 75.3J/molC

kingchemist

Fri, 2009-03-06 12:01

think about the problem - look at the units of specific heat (J per g per oC) - particularly the 'per g' part. You just need to know what the value would be for 1 mole of water, so find what 1 mol of water weighs and the answer should be evident

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chrisf

Fri, 2009-03-06 09:12

Permalink

## Re: specific heat

I'm pretty sure....

4.18J/gC * (18.02g/mol) = 75.3J/molC

kingchemist

Fri, 2009-03-06 12:01

Permalink

## Re: specific heat

think about the problem - look at the units of specific heat (J per g per oC) - particularly the 'per g' part. You just need to know what the value would be for 1 mole of water, so find what 1 mol of water weighs and the answer should be evident