Calculating value of Kp for variations of a given reaction such as reverse reaction, half quantities
For the reaction below, Kp = 6.0 104 at a certain temperature.
H2(g) + Br2(g) 2 HBr(g)
What is the value of Kp for the following reactions at this temperature?
(a) HBr(g)=1/2 H2(g) + 1/2 Br2(g)
(b) 2 HBr(g)= H2(g) + Br2(g)
(c) 1/2 H2(g) + 1/2 Br2(g) =HBr(g)
If someone can show me how to do one I'm pretty sure I can follow the same steps to do the other two.
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