In the reaction P 4 + 6 H 2 → 4 PH 3 order with respect to P4 & H2 is 0 and 1 respectively .Write the rate law of the reaction .

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Explanation: 

In order to write the rate law we multiply the concentration fo each reactant with order of each reactant raised as the powers .So, in general Order with respect to A = n

  • Order with respect to B = mRate law equation
  • Order with respect to A = n
  • Order with respect to C = p

so, far the reaction given above the order with respect to P4 is 0 and H2 is 1 so, the rate law is

rate = k[H2]1[P4]0

      =  k [H2]  

Answer: 

rate = k [H2]  

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