The reaction H2 (g) + I2 (g) <-----> 2HI (g) Keq = 50 at 448 0C will be favored in the reverse direction or forward direction ?


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For this problem the concept that you need  to remember is that  the Keq sign tells us the direction of the reaction equilibrium.

If the Keq is greater than 1 the the reaction favors the forward direction but if the Keq is less then 1 a reaction favors the reverse direction .

For the reaction given above the Keq is 50 which is greater then 1 which means this reaction is favored in the forward direction



Since the equilibrium constant Keq is 50 which is greater then 1 this reaction is favored in  the forward direction.