In this reaction 4Al + 3O2 ------> 2Al2O3 how many moles of O2 are needed with 7 moles of Al ?

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Explanation: 

4Al + 3O2 ------> 2Al2O3

In the given reaction 4 moles of Al are reacting with 3 moles of O2  so, number of moles of O2 required to react with 7 moles of Al can be calculated as :

4 moles of Al x 3 moles of O2 / 7 moles of Al = 1.71 moles of O2

Answer: 

1.71 moles of O2