The rate law for the reaction 2NO(g) + O2 (g) -----> 2NO2 (g) is Rate = k[NO]2[O2].What happens to the rate when concentration of NO is doubled ?

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Explanation: 

In the rate law  Rate = k[NO]2[O2] , the order with respect to the NO is 2

so , if we double the concentration [NO] of NO the rate will be four time means quadruples .

Answer: 

the rate will be four times

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