Mercury(I) chloride, Hg2Cl2.It has a Ksp equal to 1.3 × 10 − 18.What is the solubility of Hg2Cl2 ?

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Explanation: 

The Solubility equilibrium is :

Hg2Cl2(s) <----->  Hg2 2+(aq) + 2Cl-(aq)
Solubility-product constant expression:
 
Ksp= [Hg22+][Cl-]2
now create an ICE equation :
 
        Hg2Cl2(s) <----->  Hg2 2+(aq) + 2Cl-(aq)
 I                                     0                      0
C                                  +x                      +x
E                                   -x                      -x
 
note that the concentration of Cl- ion would be twice the concentration of the Hg since the ratio of Hg2Cl2 is 1:2
Ksp = X.(2X)2
1.3  × 10 − 18 =x. 4x2
 
Ksp = 4X3
1.3 × 10-18 = 4x3
x3= 3.25 × 10-19
x= 6.88 × 10-7M

      

 
 
Answer: 

6.88 × 10-7M

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