Kc for the reaction N2(g) + 3H2(g) <----------> 2NH3 (g) is 9.60 at 300 c . Calculate the Kp for this reaction .

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Explanation: 

The relationship between Kc and Kp is given by equation :

Kp = Kc (RT)delta n.

In the reaction given above there are 2 mol of gaseous products (2NH3) and 4 mol of gaseous reactants (1N2 + 3H2 ) . Therefore, delta n = 2-4 = -2

( remember that delta functions are always based on products minus reactant .)

Convert given temperature to kelvin 300 + 273 = 573 K

The value of ideal gas constant is R = 0.0821 L-atom/mol -K .Using Kc = 9.60

Kp = Kc (RT)delta n

    = (9.60) ( 0.0821 x 573 )-2 = 4.34 x 10^-3

 

 

Answer: 

4.34 x 10^-3