Explanation:

For this solve for k from the integral rate law equation ;

[A]t / [A]o = e^{−kt}

k=−ln[A]_{t} / [A]_{o} / t

ln 0.375g/3g / 36 min = 0.0578 min−1

t1/2=ln2 / k

= 0.693 / 0.058 = 12 min.693.693 .693

t1/2=ln2k

k=−ln[A]t[A]ot

e−k

Answer:

12 min

Topic: